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LeetCode 96 - Unique Binary Search Trees | Python | Visually Explained
LeetCode 96 — how many distinct BSTs can you build with nodes 1 to n? Pick each node as root, multiply left × right subtree counts, sum over all roots. Since count depends only on size, not values, you compute each subproblem once. That's DP in O(n²). Bonus: the answers are the Catalan numbers. #algorithm #binarytree #leetcode # ...
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